Q175
It is desired to find three-tap causal filter which gives zero signal as an output to and input of the form \[x [ n ] = c_1 ( - j n2 ) + c_2 ( j n2 ),\] Where c1 and c2 are arbitrary real numbers. The desired three-tap filter is given by h[0] = 1, h[1] = a, h[2] = b and h[n] = 0 for n 2. What are the values of the filter taps a and b if the output is y[n] = 0 for all n, when x[n] is as given above? \[ x [ n ] array*20c n = 0 \\ \\ h [ n ] = \ 1,a,b \ array y [ n ] = 0\]
It is desired to find three-tap causal filter which gives zero signal as an output to and input of the form
Where c1 and c2 are arbitrary real numbers. The desired three-tap filter is given by
h[0] = 1, h[1] = a, h[2] = b and h[n] = 0 for n < 0 or n > 2.
What are the values of the filter taps a and b if the output is y[n] = 0 for all n, when x[n] is as given above?
\xrightarrow{{x\left[ n \right]}}\boxed{\begin{array}{*{20}{c}} {n = 0} \\ \downarrow \\ {h\left[ n \right] = \left\{ {1,a,b} \right\}} \end{array}}\xrightarrow{{y\left[ n \right] = 0}}
Where c1 and c2 are arbitrary real numbers. The desired three-tap filter is given by
h[0] = 1, h[1] = a, h[2] = b and h[n] = 0 for n < 0 or n > 2.
What are the values of the filter taps a and b if the output is y[n] = 0 for all n, when x[n] is as given above?
\xrightarrow{{x\left[ n \right]}}\boxed{\begin{array}{*{20}{c}} {n = 0} \\ \downarrow \\ {h\left[ n \right] = \left\{ {1,a,b} \right\}} \end{array}}\xrightarrow{{y\left[ n \right] = 0}}
A.
a = -1, b = 1
B.
a = 0, b = 1
AnswerC.
a = 1, b = 1
D.
a = 0, b = -1
Answer: Option B
Solution
Answer: Option B
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