Q135
Let y[n] denote the convolution of h[n] and g[n], where h[n] = ( 1/2 )^n u[n] and g[n] is a causal sequence. If y[0] = 1 and y[1] = 1/2, then g[1] equals
Let y[n] denote the convolution of h[n] and g[n], where h[n] = u[n] and g[n] is a causal sequence. If y[0] = 1 and y[1] = then g[1] equals
A.
0
AnswerB.
C.
1
D.
Answer: Option A
Solution
Answer: Option A
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