Q44
Solution of the variables x1 and x2 for the following equations is to be obtained by employing the Newton-Raphson iterative method equation (i) 10x2 sin x1 - 0.8 = 0 equation (ii) 10 x_2^2 - 10x2 cos x1 - 0.6 = 0 Assuming the initial values x1 = 0.0 and x2 = 1.0, the Jacobian matrix is
Solution of the variables x1 and x2 for the following equations is to be obtained by employing the Newton-Raphson iterative method
equation (i) 10x2 sin x1 - 0.8 = 0
equation (ii) 10 - 10x2 cos x1 - 0.6 = 0
Assuming the initial values x1 = 0.0 and x2 = 1.0, the Jacobian matrix is
equation (i) 10x2 sin x1 - 0.8 = 0
equation (ii) 10 - 10x2 cos x1 - 0.6 = 0
Assuming the initial values x1 = 0.0 and x2 = 1.0, the Jacobian matrix is
A.
\left[ {\begin{array}{*{20}{c}}
{10}&{ - 0.8} \\
0&{ - 0.6}
\end{array}} \right]
B.
\left[ {\begin{array}{*{20}{c}}
{10}&0 \\
0&{10}
\end{array}} \right]
AnswerC.
\left[ {\begin{array}{*{20}{c}}
0&{ - 0.8} \\
{10}&{ - 0.6}
\end{array}} \right]
D.
\left[ {\begin{array}{*{20}{c}}
{10}&0 \\
{10}&{ - 10}
\end{array}} \right]
Answer: Option B
Solution
Answer: Option B
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