In the Newton-Raphson method, an initial guess of x0 = 2 is made and the sequence x0, x1, x2 ... is obtained for the function 0.75x3 - 2x2 - 2x + 4 = 0
Consider the statements
I. x3 = 0.
II. The method converges to a solution in a finite number of iterations.
Which of the following is TRUE?
While numerically solving the differential equation dxdy+2xy2=0,y(0)=1 using Euler's predictor-corrector (improved Euler-Cauchy) with a step size of 0.2, the value of y after the first step is
When the Newton-Raphson method is applied to solve the equation f(x) = x3 + 2x - 1 = 0, the solution at the end of the first iteration with the initial guess value as x0 = 1.2 is
The matrix \left[ {\text{A}} \right] = \left[ {\begin{array}{*{20}{c}}
2&1 \\
4&{ - 1}
\end{array}} \right] is decomposed into a product of a lower triangular matrix x[L] and an
upper triangular matrix [U]. The properly decomposed [L] and [U] matrices respectively are
Consider a differential equation dxdy(x)−y(x)=x with the initial condition y(0) = 0. Using Euler's first order method with a step size of 0.1, the value of y(0.3) is
Consider an ordinary differential equation dtdx=4t+4. If x = x0 at t = 0, the increment in x calculated using Runge-Kutta fourth order multistep method with a step size of Δt = 0.2 is
Consider p(s) = s3 + a2s2 + a1s + a0 with all real coefficients. It is known that it is derivative p'(s) has no real roots. The number of real roots of p(s) is
The differential equation dtdx=[τ1−x] is discretised using Euler's numerical integration method with a time step ΔT > 0. What is the maximum permissible value of ΔT to ensure stability of the solution of the corresponding discrete time equation?
The value of the function f(x) is given at n distinct values of x and its value is to be interpolated at the point x⋆, using all the n points. The estimate is obtained first by the Lagrange polynomial, denoted by IL and then by the Newton polynomial, denoted by IN. Which one of the following statements is correct?
The extremum (minimum or maximum) point of a function f(x) is to be determined by solving dxdf(x)=0 using the Newton-Raphson method. Let f(x) = x3 - 6x and x0 = 1 be the initial guess of x. The value of x after two iterations (x2) is