Steam undergoes isentropic expansion in a turbine from 5000 kPa and 4…

Question

Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg.K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg.K, entropy of saturated vapour = 7.2234 kJ/kg.K) The exit condit…

Accepted Answer

Option A. Superheated vapour. Answer & Solution Answer: Option A Solution: For an isentropic process s initial = s final ( exit ) & 6.65 = S_liq + x ( S_liq - S_v ) & 6.63 = 1.4336 + x ( 7.2234 - 1.4336 ) & x = 0.9 So, we are getting partially condensed vapour with quality = 0.9.

Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg.K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg.K, entropy of saturated vapour = 7.2234 kJ/kg.K) The exit condition of steam is

Solution