The difference in percentage between the accidents involving two-wheelers and other objects is respectively.

Answer: Option D

Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Percentage of accidents involving two wheelers = $$\frac{230}{1000}$$ × 100 = 23%
Percentage of accidents involving two wheelers and other subjects = $$\frac{770\times 100}{1000}$$   = 77%
∴ Required difference = 77 - 23 = 54%