The internal energy of an incompressible fluid depends upon its

Answer: Option B

$$dU=CvdT-\left[P+T\left(\frac{\left(\frac{\partial V}{\partial T}\right)P}{\left(\frac{\partial V}{\partial P}\right)T}\right)dV\right]$$       Since in case of incompressible fluid
$$\begin{array}{rl}& dV=0\\ & \Rightarrow dU=C_{V}dT\end{array}$$
So, internal energy is a function of temperature only.