Q31
The Laplace transform of a continuous-time signal x(t) is X ( s ) = 5 - s s^2 - s - 2. If the Fourier transform of this signal exists, then x(t) is
The Laplace transform of a continuous-time signal x(t) is If the Fourier transform of this signal exists, then x(t) is
A.
e2tu(t) - 2e-tu(t)
B.
-e2tu(-t) + 2e-tu(t)
C.
-e2tu(-t) - 2e-tu(t)
AnswerD.
e2tu(-t) - 2e-tu(t)
Answer: Option C
Solution
Answer: Option C
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