Q8
The matrix \[ [ A ] = [ array*20c 2&1 \\ 4& - 1 array ]\] is decomposed into a product of a lower triangular matrix x[L] and an upper triangular matrix [U]. The properly decomposed [L] and [U] matrices respectively are
The matrix \left[ {\text{A}} \right] = \left[ {\begin{array}{*{20}{c}}
2&1 \\
4&{ - 1}
\end{array}} \right] is decomposed into a product of a lower triangular matrix x[L] and an
upper triangular matrix [U]. The properly decomposed [L] and [U] matrices respectively are
A.
\left[ {\begin{array}{*{20}{c}}
1&0 \\
4&{ - 1}
\end{array}} \right]{\text{ and }}\left[ {\begin{array}{*{20}{c}}
1&1 \\
0&{ - 2}
\end{array}} \right]
B.
\left[ {\begin{array}{*{20}{c}}
2&0 \\
4&{ - 1}
\end{array}} \right]{\text{ and }}\left[ {\begin{array}{*{20}{c}}
1&1 \\
0&1
\end{array}} \right]
C.
\left[ {\begin{array}{*{20}{c}}
1&0 \\
4&1
\end{array}} \right]{\text{ and }}\left[ {\begin{array}{*{20}{c}}
2&1 \\
0&{ - 1}
\end{array}} \right]
D.
\left[ {\begin{array}{*{20}{c}}
2&0 \\
4&{ - 3}
\end{array}} \right]{\text{ and }}\left[ {\begin{array}{*{20}{c}}
1&{0.5} \\
0&1
\end{array}} \right]
AnswerAnswer: Option D
Solution
Answer: Option D
No explanation is given for this question Let's Discuss on Board