Q181
The minimum step-size required for a Delta-Modulator operating at 32 k samples/sec to signal (here u(t) is the unit-step function) x(t) = 125t(u(t) - u(t - 1)) + (250 - 125t)(u(t - 1) - u(t - 2)) so that slope-overload is avoided, would be
A.
2-10
B.
2-8
AnswerC.
2-6
D.
2-4
Answer: Option B
Solution
Answer: Option B
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