The probability that a card drawn from a pack of 52 cards will be a diamond or a king is -

Answer: Option B

Here, n(S) = 52
There are 13 cards of diamond (including one king) and there are three more kings.
Let E = event of getting a diamond or a king
Then, n(E) = (13 + 3) = 16
$$\therefore P(E)=\frac{n(E)}{n(S)}=\frac{16}{52}=\frac{4}{13}$$