What is the probability of getting a sum 9 from two throws of a dice ?

Answer: Option C

In two throws of dice, n(S) = (6 × 6) = 36
Let E = event of getting a sum 9 = [(3, 6), (4, 5), (5, 4), (6, 3)]
$$\therefore P(E)=\frac{n(E)}{n(S)}=\frac{4}{36}=\frac{1}{9}$$