The temperature of a gas in a closed container is 27° C. If the temperature of the gas is incresed to 300° C, then the pressure exerted is

Answer: Option A

According to Gay-Lussac's Law, for a gas at constant volume, the pressure is directly proportional to the absolute temperature: P ∝ T.

First, convert the given temperatures to Kelvin:

Initial temperature (T₁): 27°C + 273 = 300 K

Final temperature (T₂): 300°C + 273 = 573 K

Using the formula P₂ = P₁ × (T₂ / T₁):

P₂ = P₁ × (573 / 300) ≈ P₁ × 1.91

This shows that the final pressure is approximately 1.91 times the initial pressure, which is nearly double.

Therefore, the pressure exerted is best described as doubled.