Which of the following is correct?

x \to 0 lim (\frac{sin 4 x}{sin 2 x}) = 1 and x \to 0 lim (\frac{tan x}{x}) = 1

x \to 0 lim (\frac{sin 4 x}{sin 2 x}) = \infty and x \to 0 lim (\frac{tan x}{x}) = 1

x \to 0 lim (\frac{sin 4 x}{sin 2 x}) = 2 and x \to 0 lim (\frac{tan x}{x}) = \infty

x \to 0 lim (\frac{sin 4 x}{sin 2 x}) = 2 and x \to 0 lim (\frac{tan x}{x}) = 1

Answer

Answer: Option D

Answer: Option D

No explanation is given for this question Let's Discuss on Board