Aptitude · all questions

Algebra
practice.

Practice every MCQ with options. Use Show answers when you want the correct option and solution.

548

Questions

15/28

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Q281

Open question

\frac{a}{b} + \frac{b}{a} = 1,

then the value of a³ + b³ will be?

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Q282

Open question

If p = 99, then the value of p(p² + 3p + 3) will be?

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Q283

Open question

If a - b = 1 and a³ - b³ = 61, then the value of ab will be?

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Q284

Open question

x^{2} + 5 x + 6 = 0,

then the value of

\frac{2 x}{x ^{2} - 7 x + 6}

is?

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Q285

Open question

If a + b = 5 and a - b = 3, then the value of (a² + b²) is?

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Q286

Open question

x = a + \frac{1}{a}

and

y = a - \frac{1}{a},

then the value of x⁴ + y⁴ - 2x²y² is?

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Q287

Open question

x + \frac{1}{x} = 3,

then find the value of

x^{3} + \frac{1}{x ^{3}}

= ?

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Q288

Open question

2 x - \frac{1}{2 x} = 5,

x \neq = 0,

then find the value of

x^{2} + \frac{1}{16 x ^{2}} - 2

= ?

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Q289

Open question

x = \frac{1}{( 2 + 1 )},

the value of x² + 2x - 1 is?

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Q290

Open question

x + \frac{1}{x} = 13,

then

\frac{3 x}{( x ^{2} - 1 )}

equal to?

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Q291

Open question

If a(x + y) = b(x - y) = 2ab, then the value of 2(x² + y²) is?

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Q292

Open question

2 x + \frac{1}{4 x} = 1,

then the value of

x^{2} + \frac{1}{64 x ^{2}}

is?

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Q293

Open question

x

y

= 1,

x

y

= 17, then

x y

= ?

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Q294

Open question

3 + \frac{1}{3},

then the value of

(x - \frac{126}{42})

(x - \frac{1}{x - \frac{2 3}{3}})

is?

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Q295

Open question

\frac{2 + a}{a}

\frac{2 + b}{b}

\frac{2 + c}{c}

= 4, then the value of

\frac{ab + b c + c a}{ab c}

is?

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Q296

Open question

x + \frac{1}{x} = 5,

then the value of

\frac{5 x}{x ^{2} + 5 x + 1}

is?

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Q297

Open question

\frac{1}{a} (a^{2} + 1) = 3,

then the value of

\frac{a ^{6} + 1}{a ^{3}}

= ?

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Q298

Open question

If (x - 5)² + (y - 2)² + (z - 9)² = 0, then the value of (x + y - z) is?

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Q299

Open question

If x = 999, y = 1000, z = 1001 then the value of

\frac{x ^{3} + y ^{3} + z ^{3} - 3 x y z}{x - y + z}

is?

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Q300

Open question

\frac{a}{1 - 2 a}

+

\frac{b}{1 - 2 b}

+

\frac{c}{1 - 2 c}

\frac{1}{2},

then the value of

\frac{1}{1 - 2 a}

+

\frac{1}{1 - 2 b}

+

\frac{1}{1 - 2 c}

is?

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Algebrapractice.

Algebra
practice.