It is given that X1, X2, ... XM are M non-zero, orthogonal vectors. The dimension of the vector space spanned by the 2M vectors X1, X2 ... XM, -X1, -X2 ... -XM is
For given matrix {\text{P}} = \left[ {\begin{array}{*{20}{c}}
{4 + 3{\text{i}}}&{ - {\text{i}}} \\
{\text{i}}&{4 - 3{\text{i}}}
\end{array}} \right] where i=−1, the inverse of matrix P is
The matrix \left[ {\begin{array}{*{20}{c}}
1&2&4 \\
3&0&6 \\
1&1&{\text{p}}
\end{array}} \right] has one eigen value equal to 3. The sum of the other two eigen values is
The linear operation L(x) is defined by the cross product L(x) = b × X, where b = [0 1 0]T and X = [x1x2x3]T are three dimensional vectors. The 3 × 3 matrix M of this operation satisfies {\text{L}}\left( {\text{x}} \right) = {\text{M}}\left[ {\begin{array}{*{20}{c}}
{{{\text{x}}_1}} \\
{{{\text{x}}_2}} \\
{{{\text{x}}_3}}
\end{array}} \right].
Then the eigen values of M are
What are the value of k for which the system of equations:
(3k - 8)x + 3y + 3z = 0
3x + (3k - 8)y + 3z = 0
3x + 3y + (3k - 8)z = 0
has a not-trivial solution?
For the matrix A satisfying the equation given below, the eigen values are \left[ {\text{A}} \right]\left[ {\begin{array}{*{20}{c}}
1&2&3 \\
7&8&9 \\
4&5&6
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
1&2&3 \\
4&5&6 \\
7&8&9
\end{array}} \right]
The matrix {\text{M}} = \left[ {\begin{array}{*{20}{c}}
{ - 2}&2&{ - 3} \\
2&1&{ - 6} \\
{ - 1}&{ - 2}&0
\end{array}} \right] has eigen values -3, -3, 5. An eigen vector corresponding to the eigen value 5 is [1 2 -1]T. One of the eigen vectors of the matrix M3 is
Consider a 2 × 2 square matrix {\text{A}} = \left[ {\begin{array}{*{20}{c}}
\sigma &{\text{x}} \\
\omega &\sigma
\end{array}} \right] where x is unknown. If the eigen values of the matrix A are (σ+jω) and (σ−jω) , then x is equal to
For the given orthogonal matrix Q {\text{Q}} = \left[ {\begin{array}{*{20}{c}}
{\frac{3}{7}}&{\frac{2}{7}}&{\frac{6}{7}} \\
{ - \frac{6}{7}}&{\frac{3}{7}}&{\frac{2}{7}} \\
{\frac{2}{7}}&{\frac{6}{7}}&{ - \frac{3}{7}}
\end{array}} \right]
The inverse is