Pointer
practice.

What will be the output of the following C code?

#include <stdio.h>
void main()
{
    char *s = "hello";
    char *p = s * 3;
    printf("%c\t%c", *p, s[1]);
}

Which of the following operation is possible using a pointer char? (Assuming the declaration is char *a;)

Comment on the following C statement.

int (*a)[7];

What will be the output of the following C code?

#include <stdio.h>
int main()
{
    int *p = (int *)2;
    int *q = (int *)3;
    printf("%d", p + q);
}

Which of the following statements are true?

P. Pointer to Array
Q. Multi-dimensional array

What will be the output of the following C code?

#include <stdio.h>
void main()
{
    char *s= "hello";
    char *p = s;
    printf("%c\t%c", p[0], s[1]);
}

What will be the output of the following C code (run without any command line arguments)?

#include <stdio.h>
int main(int argc, char *argv[])
{
    while (argc--)
    printf("%s\n", argv[argc]);
    return 0;
}

What will be the output of the following C code?

#include <stdio.h>
int main()
{
    int a[4] = {1, 2, 3, 4};
    int *p = &a[1];
    int *ptr = &a[2];
    ptr = ptr * 1;
    printf("%d\n", *ptr);
}

What will be the output of the following C code?

#include <stdio.h>
void f(char *k)
{
    k++;
    k[2] = 'm';
}
void main()
{
    char s[] = "hello";
    f(s);
    printf("%c\n", *s);
}

Which of the following is not possible statically in C?

What will be the output of the following C code?

#include <stdio.h>
int main()
{
    int i = 10;
    void *p = &i;
    printf("%d\n", (int)*p);
    return 0;
}

What will be the output of the following C code?

#include <stdio.h>
void main()
{
    char *a[10] = {"hi", "hello", "how"};
    int i = 0;
    for (i = 0;i < 10; i++)
    printf("%s", *(a[i]));
}

What will be the output of the following C code?

#include <stdio.h>
int main()
{
    const int ary[4] = {1, 2, 3, 4};
    int *p;
    p = ary + 3;
    *p = 5;
    printf("%d\n", ary[3]);
}

What will be the output of the following C code?

#include <stdio.h>
void foo( int[] );
int main()
{
    int ary[4] = {1, 2, 3, 4};
    foo(ary);
    printf("%d ", ary[0]);
}
void foo(int p[4])
{
    int i = 10;
    p = &i;
    printf("%d ", p[0]);
}

How to call a function without using the function name to send parameters?

What will be the output of the following C code?

#include <stdio.h>
void main()
{
    int a[3] = {1, 2, 3};
    int *p = a;
    printf("%p\t%p", p, a);
}

Comment on an array of the void data type.

What is the syntax for constant pointer to address (i.e., fixed pointer address)?

What will be the output of the following C code (run without any command line arguments)?

#include <stdio.h>
int main(int argc, char *argv[])
{
    while (*argv  !=  NULL)
    printf("%s\n", *(argv++));
    return 0;
}

What will be the output of the following C code?

#include <stdio.h>
void m(int *p)
{
    int i = 0;
    for(i = 0;i < 5; i++)
    printf("%d\t", p[i]);
}
void main()
{
    int a[5] = {6, 5, 3};
    m(&a);
}