For an irreversible process involving only pressure-volume work

Answer: Option A

Since for an spontaneous process $$Tds>dU+PdV$$
For, constant temperature and constant pressure process the above equation can be written as
$$\begin{array}{rl}& d\left(TS-U\right)>PdV\\ & \Rightarrow d\left(-A\right)>PdV\\ & \Rightarrow {\left(dF\right)}_{T,P}<0.\end{array}$$
For spontaneous process.
Here the F is Gibbs free energy and A is Helmholtz free energy.