To do a certain work, A and B work on alternate days, with B beginning the work on the first day. A can finish the work alone in 48 days. If the work gets completed in 111/3 days, then B alone can finish 4 times the same work in:

Answer: Option C

Solution

Answer: Option C

Solution:

Let total work = 48 unit

B × 6 + A × $$\frac{16}{3}$$ = 48
B × 6 + 1 × $$\frac{16}{3}$$ = 48
B × 6 = $$\frac{128}{3}$$
B = $$\frac{64}{9}$$
4 × Total work = B × Days
Now, 48 × 4 = $$\frac{64}{9}$$ × Days
27 = Days