The value of the integral of the function g(x, y) = 4x3 + 10y4 along the straight line segment from the point (0, 0) to the point (1, 2) in the x - y plane is
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The value of x → 0 lim 2 x 4 1 − cos ( x 2 ) is
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Consider points P and Q in the x-y plane, with P = (1, 0) and Q = (0, 1). The line integral
2 P ∫ Q ( xdx + ydy ) along the semicircle with the line segment PQ as its diameter
A. is -1
B. is 0
C. is 1
D. depends on the direction (clockwise or anticlockwise) of the semicircle
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A surface S(x, y) = 2x + 5y - 3 is integrated once over a path consisting of the points that satisfy (x + 1)2 + (y - 1)2 = √2. The integral evaluates to
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Let w = f(x, y), where x and y are functions of t. Then, according to the chain rule, dt dw is equal
A. dx dw dt dx + dy dw dt dt
B. ∂ x ∂ w ∂ t ∂ x + ∂ y ∂ w ∂ t ∂ y
C. ∂ x ∂ w dt dx + ∂ y ∂ w dt dy
D. dx dw ∂ t ∂ x + dy dw ∂ t ∂ y
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For the parallelogram OPQR shown in the sketch,
OP = a t ^ + b j ^ and
OR = c t ^ + d j ^ . The area of the parallelogram is
A. ad - bc
B. ac + bd
C. ad + bc
D. ab - cd
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The distance between the origin and the point nearest to it on the surface z2 = 1 + xy is
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The value of 0 ∫ 3 0 ∫ x ( 6 − x − y ) dx dy is
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If for non-zero x, af ( x ) + bf ( x 1 ) = x 1 − 25 where a ≠ b then 1 ∫ 2 f ( x ) dx is
A. a 2 − b 2 1 [ a ( ln 2 − 25 ) + 2 47 b ]
B. a 2 − b 2 1 [ a ( 2 ln 2 − 25 ) − 2 47 b ]
C. a 2 − b 2 1 [ a ( 2 ln 2 − 25 ) + 2 47 b ]
D. a 2 − b 2 1 [ a ( ln 2 − 25 ) − 2 47 b ]
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The improper integral 0 ∫ ∞ e − 2 t dt converges to
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As x increased from − ∞ to ∞ , the function f ( x ) = 1 + e x e x
A. monotonically increases
B. monotonically decreases
C. increases to a maximum value and then decreases
D. decreases to a minimum value and then increases
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The value of x → 1 lim x 3 − 3 x 2 + 2 x 7 − 2 x 5 + 1
A. is 0
B. is -1
C. is 1
D. does not exist
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x → 0 Lim 1 − cos x x − sin x
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Let f = yx . What is ∂ x ∂ y ∂ 2 f at x = 2, y = 1?
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Given y = x
2 + 2x + 10, the value of
dx dy x = 1 is equal to
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A sphere of unit radius is centered at the origin. The unit normal at a point (x, y, z) on the surface of the sphere is the vector
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The total derivative of function xy is
A. xdy + ydx
B. xdx + ydy
C. dx + dy
D. dxdy
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x → 0 Lim ( sin ( 4 x ) e 2 x − 1 ) is equal to
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The value of the function f ( x ) = x → 0 lim 2 x 3 − 7 x 2 x 3 + x 2 is
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Consider the function f(x) = |x|3 , where x is real. Then the function f(x) at x = 0 is
A. continuous but not differentiable
B. once differentiable but not twice
C. twice differentiable but not thrice
D. thrice differentiable
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