The value of the quantity P, where P = 0 ∫ 1 x e x dx, is equal to
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What is the value of x → 4 π lim x − 4 π cos x − sin x
A. √2
B. 0
C. -√2
D. Limit does not exist
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The value of x → ∞ lim ( 1 + x 2 ) e − x is
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For a right angled triangle, if the sum of the lengths of the hypotenuse and a side is kept constant, in order to have maximum area of the triangle, the angle between the hypotenuse and the side is
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The value of x → 8 lim ( x − 8 ) x 3 1 − 2
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The vector that is NOT perpendicular to the vectors (i + j + k) and (i + 2j + 3k) is . . . . . . . .
A. (i - 2j + k)
B. (-i + 2j - k)
C. (0i + 0j + 0k)
D. (4i + 3j + 5k)
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Given
i = − 1 , what will be the evaluation of the definite integral
∫ 0 2 π cos x − i sin x cos x + i sin x dx ? Select an option to see the answer and solution.
At x = 0, the function
f ( x ) = sin L 2 π x , (-
∞ < x <
∞ , L > 0) is
A. continuous and differentiable
B. Not continuous and not differentiable
C. Not continuous but differentiable
D. Continuous but not differentiable
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The value of ∫ 0 ∞ 1 + x 2 1 dx + ∫ 0 ∞ x sin x dx is
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The values of the integrals
0 ∫ 1 0 ∫ 1 ( x + y ) 3 x − y dy dx and
0 ∫ 1 0 ∫ 1 ( x + y ) 3 x − y dx dy are
A. same and equal to 0.5
B. same and equal to -0.5
C. 0.5 and -0.5 respectively
D. -0.5 and 0.5 respectively
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a , b , c are three orthogonal vectors, Given that
a = i ^ + 2 j ^ + 5 k ^ and
b = i ^ + 2 j ^ − k ^ , the vector
c is parallel to
A. i ^ + 2 j ^ + 3 k ^
B. 2 i ^ + j ^
C. 2 i ^ − j ^
D. 4 k ^
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Given
F = ( x 2 − 2 y ) i − 4 yz j + 4 x z 2 k , the value of the line integral
c ∫ F ⋅ d l along the straight line c from (0, 0, 0) to (1,1,1) is
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At x = 0, the function f(x) = |x| has
A. a minimum
B. a maximum
C. a point of inflection
D. neither a maximum nor minimum
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A parabola x = y
2 with 0 ≤ x ≤ 1 is shown in the figure. The volume of the solid of rotation obtained by rotating the shaded area by 360° around the x-axis is
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The line integral
P 1 ∫ P 2 ( ydx + xdy ) for P
1 (x
1 , y
1 ) to P
2 (x
2 , y
2 ) along the semicircle P
1 , P
2 shown in the figure is
A. x2 y2 - x1 y1
B. ( y 2 2 − y 1 2 ) + ( x 2 2 − x 1 2 )
C. (x2 - x1 ) (y2 - y1 )
D. (y2 - y1 )2 + (x2 - x1 )2
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The angle between two unit-magnitude coplanar vectors P(0.866, 0.500, 0) and Q(0.259, 0.966, 0) will be
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The following surface integral is to be evaluated over a sphere for the given steady velocity vector field F = xi + yj + zk defined with respect to a Cartesian coordinate system having i, j and k as unit base vectors.
S ∬ 4 1 ( F ⋅ n ) dA where S is the sphere, x2 + y2 + z2 = 1 and n is the outward unit normal vector to the sphere.
The value of the surface integral is
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If a function is continuous at a point,
A. the limit of the function may not exist at the point
B. the function must be derivable at the point
C. the limit of the function at the point tends to infinity
D. the limit must exist at the point and the value of limit should be same as the value of the function at that point
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The vector that is normal to the surface 2xz2 - 3xy - 4x = 7 at the point (1, -1, 2) is
A. 2i - 3j + 8k
B. 2i + 3j + 4k
C. 7i - 3j + 8k
D. 7i - 5j + 8k
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The derivative of the symmetric function drawn in given figure will look like
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