Laplace transform of sin ht is
A. S 2 − 1 1
B. 1 − S 4 1
C. S 4 − 1 S
D. 1 − S 4 S
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Laplace transform of cos (ωt) is
A. s 2 + ω 2 s
B. s 2 + ω 2 ω
C. s 2 − ω 2 s
D. s 2 − ω 2 ω
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The Laplace transform of a function f(t) is s 2 ( s + 1 ) 1 . The function f(t) is
A. t - 1 + e-1
B. t + 1 + e-1
C. -1 + e-1
D. 2t + et
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The inverse Laplace transform of H ( s ) = s 2 + 2 s + 1 s + 3 for t ≥ 0 is
A. 2t e-t + e-t
B. 3e-t
C. 3t e-t + e-t
D. 4t e-t + e-t
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Let {\text{f}}\left( {\text{x}} \right) = \left\{ {\begin{array}{*{20}{c}}
{ - \pi ,\,\,{\text{if}}}&{ - \pi < {\text{x}} \leqslant {\text{0}}} \\
{\pi ,\,\,{\text{if}}}&{0 < {\text{x}} \leqslant \pi }
\end{array}} \right. be a periodic function of period 2π. The coefficient of sin5x in the Fourier series expansion of f(x) in the interval [-π, π] is
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Given the Fourier series in (-π, π) for f(x) = x cosx, the value of a0 will be
A. − 3 2 π 2
B. 0
C. 2
D. n 2 − 1 ( − 1 ) n 2 n
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Laplace transform of the function f(t) is given by
F ( s ) = L { f ( t ) } = ∫ 0 ∞ f ( t ) e − st dt . Laplace transform of the function shown below is given by
A. s 1 − e − 2 s
B. 2 s 1 − e − s
C. s 2 − 2 e − s
D. s 1 − 2 e − s
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If L defines the Laplace Transform of a function, L [sin (at)] will be equal to
A. s 2 − a 2 a
B. s 2 + a 2 a
C. s 2 + a 2 s
D. s 2 − a 2 s
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The Fourier series expansion of the saw-toothed waveform f(x) = x in (-π, π) of period 2π gives the series, 1 − 3 1 + 5 1 − 7 1 + ....
The sum is equal to
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Laplace transform of 8t3
A. S 4 8
B. S 4 16
C. S 4 24
D. S 4 48
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The inverse Laplace transform of the function F ( s ) = s ( s + 1 ) 1 is given by
A. f(t) = sin t
B. f(t) = e-t sin t
C. f(t) = e-t
D. f(t) = 1 - e-t
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Laplace transform analysis gives
A. Time domain response only
B. Frequency domain response only
C. Both A and B
D. None of the above
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Inverse Laplace transform of the function s 2 + 3 s + 2 s , is
A. − e − t + 2 e − 2 t
B. e − t − 2 e − 2 t
C. e − t + 2 e − 2 t
D. 2 e − t + e − 2 t
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Which of the following is the advantage of using Laplace transform techniques?
A. Permits use of simple algebra
B. Converts functions in the t -domain into s -domain
C. Initial conditions are automatically taken care of
D. All of the above
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The initial value theorem does not hold good for which of the following functions?
A. Ramp function
B. Delta function
C. Step function
D. Hyperbolic function
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Find the inverse Laplace transform of F ( s ) = s ( s + 4 ) ( s − 5 ) s 2 + 2 s − 2
A. ( 10 1 + 6 1 e − 4 t + 15 11 e 5 t ) u ( t )
B. ( 10 1 + 6 1 e 6 t + 15 10 e 5 t ) u ( t )
C. ( 1 + 6 1 e − 4 t + 15 10 e 5 t ) u ( t )
D. ( 10 1 − 6 1 e 4 t + 15 10 e − 5 t ) u ( t )
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Give transfer function H ( s ) = s 2 + s + 4 s + 2 , under steady state condition, the sinusoidal input and output are, respectively x(t) = cos 2t, y(t) = cos(2t + ϕ ), then angle ϕ will be
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Which of the following correctly defines Laplace transform of a function in the time domain?
A. L { f ( t ) } = ∫ 0 − ∞ f ( t ) e − s t d t
B. L { f ( t ) } = ∫ 0 − ∞ f ( t ) e + s t d t
C. L { f ( t ) } = ∫ 0 − ∞ f ( t ) − s t e − s t d t
D. L { f ( t ) } = ∫ 0 − ∞ f ( s ) e − s t d t
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The Laplace transform of I ( t ) is given by I ( s ) = s ( s 2 + 2 ) 5 . As t → ∞ the value of I ( t ) tends to
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Given that F ( s ) is the one-side Laplace transform of f ( t ) , the Laplace transform of ∫ 0 t f ( τ ) d τ is
A. s F ( s ) − f ( 0 )
B. s 1 F ( s )
C. ∫ 0 5 F ( τ ) d τ
D. s 1 [ F ( s ) − f ( 0 ) ]
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