The Laplace transform of i(t) is given by I(s)=s(1+s)2. As t→∞ the value of i(t) tends to
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The bilateral Laplace transform of e−1u(t+2) is
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The bilateral Laplace transform of etcos2tu(−t)+e−tu(t)+e2tu(t) is
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The bilateral Laplace transform of u(-t + 3) is
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The Laplace transform of x(t) is X(s)=e−2ss2+2s−26s2+s
The initial value of x(t) is
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The bilateral Laplace transform of e(3t+6)u(t+3) is
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The Laplace transform of x(t) is X(s)=s(s+1)(s+4)e−3s(2s2+1)
The final value of x(t) is
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The Laplace transform of x(t) is X(s)=s2+5s+12s2+3
The initial value of x(t) is
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The trigonometric Fourier series of an even function does not have the
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The inverse Laplace transform of the function (s+1)(s+3)s+5 is
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