Find the Thevenin equivalent (V
TH and R
TH ) between terminals A and B of the circuit given.
A. 562 mV, 167 Ω
B. 5.62 V, 167 Ω
C. 5.62 V, 188 Ω
D. 562 mV, 188 Ω
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In a two-source circuit, one source acting alone produces 12 mA through a given branch. The other source acting alone produces 10 mA in the opposite direction through the same branch. The actual current through the branch is
A. 22 mA
B. 12 mA
C. 10 mA
D. 2 mA
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An ideal current source has zero internal resistance.
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A practical voltage source has a nonzero internal resistance.
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An ideal voltage source has zero internal resistance.
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A practical current source has a finite internal resistance.
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A 680 Ω load resistor, RL, is connected across a constant current source of 1.2 A. The internal source resistance, RS, is 12 kΩ. The load current, RL, is
A. 0 A
B. 1.2 A
C. 114 mA
D. 1.14 A
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The Thevenin equivalent voltage (VTH ) is the short-circuit voltage between two terminals in a circuit.
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A 120 V voltage source has a source resistance, RS, of 60 Ω. The equivalent current source is
A. 2 A
B. 4 A
C. 200 mA
D. 400 mA
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A 12 mA current source has an internal resistance, RS, of 1.2 kΩ. The equivalent voltage source is
A. 144 V
B. 14.4 V
C. 7.2 V
D. 72 mV
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Find the current in R2 of the given circuit, using the superposition theorem.
A. 16.7 mA
B. 33.3 mA
C. 50 mA
D. 16.6 mA
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Norton's equivalent current (IN) is an open-circuit current between two points in a circuit.
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A certain voltage source has the values VS = 30 V and RS = 6 Ω. The values for an equivalent current source are
A. 5 A, 6 Ω
B. 30 A, 6 Ω
C. 5 A, 30 Ω
D. 30 A, 5 Ω
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A certain current source has the values IS = 4 µA and RS = 1.2 MΩ. The values for an equivalent voltage source are
A. 4.8 µV, 1.2 MΩ
B. 1 V, 1.2 MΩ
C. 4.8 V, 4.8 MΩ
D. 4.8 V, 1.2 MΩ
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You cannot convert a voltage source to an equivalent current source, or vice versa.
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