If D, E and F are the mid points of BC, CA and AB respectively of the ΔABC. The ratio of area of the parallelogram DEFB and area, of the trapezium CAFD is:
Two circles having radii r units intersect each other in such a way that each of them passes through the centre of the other. Then the length of their common chord is
In the given figure, ABC is a right-angled triangle. ∠ABC = 90° and ∠ACB = 60°. If the radius of the smaller circle is 2 cm, then what is the radius (in cm) of the larger circle?
AB and CD are two chords in a circle with centre O and AD is a diameter. AB and CD produced meet at a point P outside the circle. ∠APD = 25° and ∠DAP = 39°, then the measure of ∠CBD is:
AD is perpendicular to the internal bisector of ∠ABC of ΔABC. DE is drawn through D and parallel to BC to meet AC at E. If the length of AC is 12 cm, then the length of AE (in cm.) is
Two circles touch each other externally at T. RS is a direct common tangent to the two circles touching the circles at P and Q. ∠TPQ = 42°. ∠PQT (in degrees) is:
ABCD is a trapezium in which AB || DC and its diagonals intersect at P. If AP = (3x - 1) cm. PC = (5x - 3) cm. BP = (2x + 1) cm and PD = (6x - 5) cm, then the length of DB is:
A circle is inscribed in a quadrilateral ABCD touching AB, BC, CD and AD at the points P, Q, R and S, respectively, and ∠B = 90°. If AD = 24 cm, AB = 27 cm and DR = 6 cm, then what is the circumference of the circle?